机器学习第四章答案

A passenger plane is able to carry a fixed weight, including passengers and fuel.Which wing design would be best for such a plane?

A.Design 1

B.Design 2

C.Design 3

D.Design 4


正确答案:B

To handle the question, you need to infer that the “best” design would be one that is most efficient in terms of its lift-to-drag ratio as well as in terms of fuel consumption. Fortunately,Tables 1 and 2 each show that design 2 is most efficient.


假元推理是由合适公式W1和W1→W2产生合适公式W2的运算。()

此题为判断题(对,错)。


参考答案:对


你正在使用带有L1正则化的logistic回归做二分类,其中C是正则化参数,w1和w2是x1和x2的系数。当你把C值从0增加至非常大的值时,下面哪个选项是正确的?

A.第一个w2成了0,接着w1也成了0

B.第一个w1成了0,接着w2也成了0

C.w1和w2同时成了0

D.即使在C成为大值之后,w1和w2都不能成0


正确答案:C


You are developing a Windows Presentation Foundation (WPF) application for a travel reservation systemYou need to ensure that users can select a range of travel dates.What should you do ?()

A. Add single DatePicker control to the design surface

B. Add single Calendar control to the design surface

C. Add single MediaElement control to the design surface to display a calendar

D. Add the appropriate Windows Forms references to the project references. Add a single Windows Forms DateTimePicker control to the design surface


参考答案:B


Refer to the exhibit. Which two statements about the topologies shown are correct?()

A. Design 1 is a looped triangle design.

B. Design 2 is a looped triangle design.

C. Design 2 achieves quick convergence using RSTP.

D. Both designs supportstateful services at the aggregation layer.

E. Design 2 is the most widely deployed in enterprise data centers.


参考答案:A, D


4.1 What are the values of weights wo, wl, and w2 for the perceptron whose decision surface is illustrated in Figure 4.3? Assume the surface crosses the xl axis at -1, and the x2 axis at 2. Ans. The function of the decision surface is: 2+2x1-x2 = 0, so w0 =2, w1 = 2, w2 = -1. 4.2. Design a two-input perceptron that implements the boolean function A ? B. Design a two-layer network of perceptrons that implements A XOR B. Ans. We assume 1 for true, -1 for false. (1) A ? B: w0 = -0.8. w1 = 0.5, w2 = -0.5. x1(A) x2(B) w0+w1x1+w2x2 output -1 -1 -0.8 -1 -1 1 -1.8 -1 1 -1 0.2 1 1 1 -0.8 -1 (2) A XOR B = (A ? B) (? A B) The weights are: Hidden unit 1: w0 = -0.8, w1 = 0.5, w2 = -0.5 Hidden unit 2: w0 = -0.8, w1 = -0.5, w2 = 0.5 Output unit: w0 = 0.3, w1 = 0.5, w2 = 0.5 x1(A) x2(B) Hidden unit 1 value Hidden unit 2 value Output value-1 -1 -1 -1 -1 -1 1 -1 1 1 1 -1 1 -1 1 1 1 -1 -1 -1 4.3. Consider two perceptrons defined by the threshold expression 022110+xwxww. Perceptron A has weight values: w0 = 1, w1 =2, w2 = 1. and perceptron B has the weight values: w0 = 0, w1 = 2, w2 = 1. True or false? Perceptron A is more-generalthan perceptron B. (more-generalthan is defined in Chapter 2.) Ans. True. For each input instance x=(x1, x2), if x is satisfied by B, which means 2x1+x20, then we have 2x1+x2 +10. Hence, x is also satisfied by the A. 4.5. Derive a gradient descent training rule for a single unit with output o, where 2211110.nnnnxwxwxwxwwo+=Ans. The gradient descent is:,.,1,)(0wnEwEwEwE?=?r)( )()()()(2122ididDdddddDdddDdddxxototwiototwiwiE-=-?-=-?=?The training rule for gradient descent is:iiiwww+=, where +-=?-=DdididddiixxotwEw)(2

When is a first-hop redundancy protocol needed in the distribution layer?()

A. when HSRP is not supported by the design

B. when multiple vendor devices need to be supported

C. when preempt tuning of the default gateway is needed

D. when a robust method of backing up the default gateway is needed

E. when the design implements Layer 2 between the access switch and the distribution switch

F. when the design implements Layer 3 between the access switch and the distribution switch


参考答案:F


Refer to the exhibit. A network technician is asked to design a small network with redundancy. The exhibit represents this design, with all hosts configured in the same VLAN. What conclusions can be made about this design?()

A.The design will function as intended

B.Spanning-tree will need to be used.

C.The router will not accept the addressing scheme.

D.The connection between switches should be a trunk.

E.The router interfaces must be encapsulated with the 802.1Q protocol.


参考答案:C


某河段控制断面上游拟新增两个稳定排放源W1、W2。规划允许两个新增源在该断面COD浓度增量限值为0.5mg/L。若设计水文条件下,W1、W2在该断面的单位负荷响应系数分别为α1=0.02和

A.方案1,W1:12.5kg/d,W2:25.0kg/D
B.方案2,W1:20.0kg/d,W2:10.0kg/D
C.方案3,W1:25.0kg/d,W2:1.0kg/D
D.方案4,W1:4.0kg/d,W2:40.0kg/D

答案:A,B,D
解析:
根据题意,具体计算为:方案1,W1的COD浓度增量为:0.02×12.5=0.25(mg/L),W2的COD浓度增量为:0.01×25.0=0.25(mg/L),总增量为0.5mg/L,符合题意;方案2,W1的COD浓度增量为:0.02×20.0=0.4(mg/L),W2的CoD浓度增量为:0.01×10.0=0.1(mg/L),总增量为0.5mg/L,符合题意;方案3,W1的COD浓度增量为:0.02×25.0=0.5(mg/L),W2的COD浓度增量为:0.01×1.0=0.01(mg/L),总增量为0.51mg/L,不符合题意;方案4,W1的COD浓度增量为:0.02×4.0=0.08(mg/L),W2的COD浓度增量为:0.01×40.0=0.4(mg/L),总增量为0.48mg/L,符合题意。


(2014年)某河流控制断面上有拟建增两个稳定排放源W1、W2。规划允许两个新增源在该断面COD浓度增量限值为0.5mg/L,若涉及水文条件下,W1、W2在该断面的单位负荷响应系数分别为



则下列W1、W2的COD分配方案中,可行的有( )。

A.方案1 W1:12.5kg/d W2:25.0KG/d
B.方案2 W1:20.0KG/D W2:10.0KG/D
C.方案3 W1:25.0KG/D W2:1.0KG/D
D.方案4 W1:4KG/D W2:40.0KG/D

答案:A,B,D
解析:
方案一的浓度增量为:12.5*0.02+25*0.01=0.5mg/L;方案二的浓度增量为:20*0.02+10*0.01=0.5mg/L;方案三的浓度增量为:25*0.02+1*0.01=0.51mg/L;方案四的浓度增量为:4*0.02+40*0.01=0.48mg/L;故只有方案一、二、四满足。


设图(a)、(b)、(c)三个质量弹簧系统的固有频率分别为w1、w2、w3,则它们之间的关系是( )。



A.w1<w2=w3
B.w2<w3=w1
C.w3<w1=w2
D.w1=w2=w3


答案:A
解析:
求等效的弹簧系数,按串联、并联的公式计算是

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