A programmer is designing a class to encapsulate the information about an inventory item. A JavaBeans component is needed to do this. The Inventoryltem class has private instance variables to store the item information： 10. private int itemId； 11. private String name； 12. private String description； Which method signature follows the JavaBeans naming standards for modifying the itemld instance variable？（）
第1题：
A. It is true that j==i.
B. It is false that j==i.
C. An exception is thrown at runtime.
D. Compilation fails because of an error in line 13.
第2题：
A company that makes Computer Assisted Design (CAD) software has, within its application, some utility classes that are used to perform 3D rendering tasks. The company‘s chief scientist has just improved the performance of one of the utility classes‘ key rendering algorithms, and has assigned a programmer to replace the old algorithm with the new algorithm. When the programmer begins researching the utility classes, she is happy to discover that the algorithm to be replaced exists in only one class. The programmer reviews that class‘s API, and replaces the old algorithm with the new algorithm, being careful that her changes adhere strictly to the class‘s API. Once testing has begun, the programmer discovers that other classes that use the class she changed are no longer working properly.What design flaw is most likely the cause of these new bugs?（）
A.Inheritance
B.Tight coupling
C.Low cohesion
D.High cohesion
E.Loose coupling
F.Object immutability
第3题：
A.isPvMSysTeM
B.qUArTUsii_PrOgrAMMer_sigNALTAP
C.CPLD sOfTwAre
D.wfTP32
第4题：
字符串“programmer”中长度为4的子串有__(10)__个。
A.4
B.5
C.6
D.7
第5题：
A programmer must know about a function’s(74)to Call it correctly．
A．location
B．algorithm
C．Interface
D．statements
第6题：
A.java.lang.StackOverflowError
B.java.lang.IllegalStateException
C.java.lang.ExceptionInInitializerError
D.java.lang.ArrayIndexOutOfBoundsException
第7题：
阅读以下说明和Java代码，将应填入(n)处的字句写在对应栏内。
[说明]
本程序的功能是给公司的员工Tom，Jack，Green增加薪水。三人的职位分别是programmer， Manager，CEO。
程序由6个类组成：WorkerTest是主类，programmer，Manager，CEO三个类，薪水增加的规则是 programmer的涨幅是5%；Manager的是10%；CEO也是Manager，但是它除了有Manager的涨幅，还有1000元的bonus。接口SalaryRaise提供了一个增加薪水的方法raise()。
[java程序]
public class WorkerTest {
public WorkerTest( ) {}
public static void main( String[] args) {
Programmer programmer = new Programmer( "Tom" ,3000);
Manager manager = new Manager( "Jack" ,4000);
CEO ceo = new CEO( "Green" ,4000);
Worker [] worker = new Worker[3];
programmer, raise( );
manager, raise( );
ceo. raise( );
worker[0] = programmer;
worker [1] = manager;
worker[2] = ceo;
for ( int i = 0 ;i ＜ worker, length; i + + ) {
System. out. prinfln (" Name:" + worker [i]. getName ( ) +" \ tSalary:" + worker [i]. getSalary ());
public interface SalaryRaise { void raise( ); }
public class Worker {
public String name;
public double (1);
public Worker( ) {}
public String getName( ) {return name;}
public void setName( String name) {this. name = name;}
public double getSalary( ) {return salary;}
public void setSalary(double salary) { this. salary = salary; }
}
public class Programmer extends Worker implements (2) {
public Programmer( ) {}
public void raise( ) {
double pets=0.05;
double sala = this. getSalary( ) * (1 + pers);
this. setSalary (sala);
public Programmer( Siring name, double salary) t
this. name = name;
this. salary = salary;
public class Manager extends (3) implements SalaryRaise {
public Manager( ) { }
public Manager(String name, double salary) {
this. name = name;
this. salary = salary;
}
public void raise( ) {
double pets = 0.1;
double sala = this. getSalary() * (1 + pers);
this. setSalary(sala);
}
}
public class CEO extends Manager implements SalaryRaise {
public CEO() {}
public CEO( String name,double salary) {
this. name = name;
this. salary = salary;
}
public void raise( ) {
double bonus = 1000;
(4);
double sala = this. getSalary( );
(5);
this. setSalary(sala);
}
}
第8题：
【S4】
A．poet
B．architect
C．doctor
D．programmer
第9题：
A programmer must know about a function's ______ to call it correctly.
A．location
B．algorithm
C．Interface
D．statements
第10题：
In object-oriented(51), objects can be viewed as reusable components, and once the programmer has developed a(52)of these components, he can(53)the amount of new coding required. But(52)a(54)is no simple task because the integrity of the Original software design is critical. Reusability can be a mixed blessing for user, too, as a programmer has to be able to find the object he needs. But if(55)is your aim, reusability is worth the risk.
A．programming
B．creating
C．indisposing
D．library
E．maximize