深圳力维智联技术有限公司2月招聘面试题154道202026

D

Anne and Joseph are talking about an interesting question. Why do some people change their names? There can be many reasons. Hanna changed her name to Anne because she thought it would be easier for people to remember. On the other hand, Joseph is thinking about changing his name to an unusual name because he wants to be different.

People have a lot of reasons for changing their names. Film stars, singers, sportsmen and some other famous people often change their names because they want names that are not ordinary, or that have special sound. They chose the “new name” for themselves instead of the name their parents gave them when they were born.

Some people have another reason for changing their names. They have moved to a new country and want to use a name that is usual there. For example, Li Kaiming changed his name to Ken Lee when he moved to the United States. He uses the name Ken at his job and at school. But with his family and Chinese friends, he uses Li Kaiming. For some people, using different names makes life easier in their new country.

In many countries, a woman changes her family name to her husband’s after she gets married. But today, many women are keeping their own family name and not using their husband’s. Sometimes , women use their own name in some situations (情况)and their husband’s in other situations . And some use both their own name and their husband’s.

根据短文内容,完成下面表格。

different people

reason to change the name

Hanna

It is ____61____ for people to remember.

Joseph

He wants to have a name that’s ____62_____.

famous people

Their name may sound _____63_____.

Li Kaiming

Using different names can make ____64_____ easier.

a woman

After she gets _____65_____, she may change her name.

61._________________________________________________________________________


正确答案:
easier


Both Chinese names and English names give clues about place identity, family relationship, ethnic group, parents' expectation and values or even personal().

A、mistakes

B、characteristics

C、replacement

D、analysis


参考答案:B


When you meet a group of people, it is better to remember __

A. all their names B. a couple of names first

C. just their last names D. as many names as possible


正确答案:B


关于group by 以下语句正确的是( )

A.SELECT store_name FROM Store_Information GROUP BY store_name

B. SELECT SUM(sales) FROM Store_Information GROUP BY sales

C.SELECT store_name, price SUM(sales) FROM Store_Information GROUP BY store_name,price

D.SELECT store_name, SUM(sales) FROM Store_Information GROUP BY store_name


正确答案:D,C,B 


What are the components of Chinese names?

A、Given name and middle names

B、Family name

C、Family name and given name

D、Last name and surname


参考答案:C


深圳力维智联技术有限公司2月招聘面试题面试题面试官常问到的一些题目整理如下:问题 Q1:Python中的lambda是什么?可用的回答 :它是一个单独的表达式匿名函数,通常用作内联函数。问题 Q2:列表的扁平化和降维?比如有一个二维列表,降成普通的一维的。如:groups = huahua, xiaojian, musen, yuze, keyou得到结果 huahua, xiaojian, musen, yuze, keyou可用的回答 : 方法一:最简单的方式可以通过 for 循环的方式一一提取: names = for group in groups: for name in group: names.append(name) print(names) 方法二:但是在面试的时候可能会加一些限制,比如让你用一行代码实现 这个时候就需要对 python 基础有进一步的理解了,比如说使用 sum 函数: names = sum(groups, ) 方法三:通过列表推导式也可以方便的解决: a = e for group in groups for e in group 问题 Q3:如何提高爬取效率?可用的回答 : 爬虫下载慢主要原因是阻塞等待发往网站的请求和网站返回 1,采用异步与多线程,扩大电脑的cpu利用率; 2,采用消息队列模式 3,提高带宽 问题 Q4:说一下Django,MIDDLEWARES中间件的作用?可用的回答 : 中间件是介于request与response处理之间的一道处理过程,相对比较轻量级,并且在全局上改变django的输入与输出。 问题 Q5: scrapy的优缺点?为什么要选择scrapy框架?可用的回答 : 优点: 采取可读性更强的xpath代替正则强大的统计和log系统 同时在不同的url上爬行 支持shell方式,方便独立调试 写middleware,方便写一些统一的过滤器 通过管道的方式存入数据库 缺点: 基于python爬虫框架,扩展性比较差,基于twisted框架, 运行中exception是不会干掉reactor,并且异步框架出错后是不会停掉其他任务的,数据出错后难以察觉 问题 Q6:.什么是关联查询,有哪些?可用的回答 :将多个表联合起来进行查询,主要有内连接、左连接、右连接、全连接(外连接)问题 Q7:如何跨模块共享全局变量?可用的回答 :要在单个程序中跨模块共享全局变量,请创建一个特殊模块。在应用程序的所有模块中导入配置模块。该模块将作为跨模块的全局变量提供。问题 Q8:谷歌的无头浏览器?可用的回答 : 无头浏览器即headless browser,是一种没有界面的浏览器。既然是浏览器那么浏览器该有的东西它都应该有,只是看不到界面而已。 Python中selenium模块中的PhantomJS即为无界面浏览器(无头浏览器):是基于QtWebkit的无头浏览器。 问题 Q9:简述 生成器、迭代器、可迭代对象 以及应用场景?可用的回答 : Python可迭代对象(Iterable) Python中经常使用 for 来对某个对象进行遍历,此时被遍历的这个对象就是可迭代对象,像常见的 list , tuple 都是。 如果给一个准确的定义的话,就是只要它定义了可以返回一个迭代器的 _iter_ 方法, 或者定义了可以支持下标索引的 _getitem_ 方法,那么它就是一个可迭代对象。 Python迭代器(iterator) 迭代器是通过 next() 来实现的,每调用一次他就会返回下一个元素,当没有下一个元素的时候返回一个 StopIteration 异常, 所以实际上定义了这个方法的都算是迭代器。 Python生成器(Generators) 生成器是构造迭代器的最简单有力的工具,与普通函数不同的只有在返回一个值的时候使用 yield 来替代 return , 然后 yield 会自动构建好 next() 和 iter() 因为迭代器如此普遍,python专门为for关键字做了迭代器的语法糖。 在for循环中,Python将自动调用工厂函数iter()获得迭代器,自动调用next()获取元素,还完成了检查StopIteration异常的工作。 问题 Q10:Python里面match()和search()的区别?可用的回答 :re模块中match(pattern,string,flags),检查string的开头是否与pattern匹配。re模块中research(pattern,string,flags),在string搜索pattern的第一个匹配值。算法题面试官常问到的一些算法题目整理如下(大概率会机考):算题题 A1:根据中序和后序遍历结果中构建二叉树题目描述如下:Given inorder and postorder traversal of a tree, construct the binary tree.Note:You may assume that duplicates do not exist in the tree.For example, giveninorder = 9,3,15,20,7postorder = 9,15,7,20,3Return the following binary tree: 3 / 9 20 / 15 7这个的思路与之前的大同小异。inorder:左 根 右postorder:左 右 根postorder 中找根,inorder 中找左右。下面是一个递归实现。left_inorderleft_postorder和right_inorderright_postorder的处理。一开始全部中规中矩的定义清晰,然后root.left, root.right。完成所有测试大概需要 200ms 左右。后面发现并不需要:postoder 是 左 右 根。根完了就是右,所以直接可以postorder.pop(),然后先进行 right 的查找,相当于 right_postorder 带了一些另一颗树的东西,不过无关紧要。都是些优化的步骤。 测试地址:https:/

哪个选项是下面代码的执行结果()name="Python语言程序设计课程"print(name[0],name[2:-2],name[-1])

A、Pthon语言程序设计课课

B、Pthon语言程序设计课

C、Pthon语言程序设计程

D、Pthon语言程序设计课程


答案:C


It's very interesting to study names of different countries.Chinese names are different (1) foreign names.Once an English lady came to visit me.When I was introduced to her she said, “ Glad to meet you, Miss Ping.” Then she gave me her name card with three words on it:"Betty J.Black.So I said, “Thank you, Miss Betty.” We looked at each other and laughed heartily.Later I found that the English people (2)their family names last and the given names first, while their middle names are not used very much.I explained to her that the Chinese family name comes first, the given name last, so she(3) never call me Miss Ping.She asked if we Chinese had a middle name.I told her we didn't.but people may often find three words

on a Chinese name card.In this case the family name still come first, and the other words after it(4)a two-word given name.it is quite usual in China.My sister is Li Xiaofang.She has two words in her given name instead (5) just one like mine.(完型填空)

A.Put

B.From

C.Should

D.of

E.are


答案:B A C E D 

解析:本段意思:研究不同国家的名称是非常有趣的。中国人的名字不同于外国人的名字。有一次,一位英国女士来看我。当我被介绍给她时,她说:“很高兴认识你,萍小姐。然后她给了我她的名片,上面有三个字:“贝蒂·j·布莱克。”所以我说:“谢谢你,贝蒂小姐。我们面面相觑,开怀大笑。后来我发现英国人把姓放在最后,名放在前面,中间的名字用得不多。我向她解释中国姓在前,名在后,所以她永远不要叫我萍小姐。她问我们中国人有没有中间名。我告诉她我们没有。但是人们经常会在一张中文名片上发现三个字。在这种情况下,姓仍然在前面,在它后面的其他单词是两个单词组成的名字。这在中国很常见。我妹妹是李小芳。她有两个字在她的名字,而不像我一样只有一个。



Your network consists of a single Active Directory domain.The domain contains more than 300 group objects. The group objects are divided between several regional organizational units (OUs).You need to create a list of all groups that have names that begin with the word Sales.Which command should you use? ()

A. Dsget group

B. Dsquery group

C. Netdom query

D. Net group


参考答案:B


阅读下列函数说明和C++代码,将应填入(n)处的字句写在对应栏内。

[说明]

在一些大型系统中,大多数的功能在初始化时要花费很多时间,如果在启动的时候,所有功能(包括不用的功能)都要全面初始化的话,会导致应用软件要花很多时间才能启动。因此常将程序设计成到了实际要使用某种功能的阶段才初始化该功能。

以下示例展示了Proxy(代理)模式,PrinterProxy类执行一些比较“轻”的方法,需要真正执行“重”的方法时才初始化Print类。图5-1显示了各个类间的关系。

[图5-1]

[C++代码]

class Printable{

public:

virtual void setPrinterName(string name)=0;

virtual string getprinterName()=0;

virtual void print(string name)=0;

};

class Printer:public Printable{

private:

string name;

public:

Printer(string name){

cout<<"正在产生Printer的对象实例"<<endl;

this->name=name;

}

void setPrinterName(string name){

this->name=name;

}

string getPrinterName(){

return name;

}

void print(string msg){

cout<<"======="<<name<<"==========="<<endl;

cout<<msg<<endl;

}

};

class printerproxy :public (1) {

private:

String name;

Printer *real;

public:

PrinterProxy(string name){

(2)=NULL;

this->name=name;

}

void setPrinterName(string name){

if((3))real->setPrinterName(name);

this->name=name;

}

string getPrinterName(){

return name;

}

void print(string msg){

(4);

real->print(msg);

}

void realize(){

if(real==NULL)real=(5);

}

};

(1)


正确答案:Printable
Printable


有如下程序:

#include<iostream>

using flamespace std;

class Name{

char name[20];

public:

Name(){

strcpy(name,“”); cout<<‘?’;

}

Name(char*fname){

strcpy(name,fname); cout<<‘?’;

}

};

int main(){

Name names[3]={Name(”张三”),Name(”李四”)};

return 0;

}

运行此程序输出符号?的个数是

A.0

B.1

C.2

D.3


正确答案:D
解析:定义了3个Name的对象,前2个定义带参数,执行第二个构造函数输出“?”,第三个定义没带参数,执行第一个构造函数也输出“?”;一共输出3个“?”,故选D)。

更多 “深圳力维智联技术有限公司2月招聘面试题154道202026” 相关考题
考题 多选题Which of the following statements are true when creating NETBIOS names? ()ANETBIOS names can only use alphanumeric characters.BYou can use a ’.’ in a NETBIOS name.CYou can use an ’_’ (underscore) in a NETBIOS name.DNETBIOS names must be UPPERCASEENETBIOS names can be a maximum of 32 characters正确答案:D,A解析:暂无解析

考题 以下哪种初始化数组的方式是错误的?()  A、String[] name =,“zhang”,”wang”,”li”-B、String*3+ names=,“zhang”,”wang”,”li”-C、String names[] =new String[3]  names*0+=”wang”D、names*1+=”wang”E、names*2+=”li”F、以上皆正确正确答案:B

考题 单选题以下哪种初始化数组的方式是错误的?()A String[] name =,“zhang”,”wang”,”li”-B String*3+ names=,“zhang”,”wang”,”li”-C String names[] =new String[3]  names*0+=”wang”D names*1+=”wang”E names*2+=”li”F 以上皆正确正确答案:A解析:暂无解析

考题 多选题你使用VisualStudio.NET为在线游戏创建一个基于Windows的应用程序。每个用户都将可以在他们各自的电脑上运行这个客户端应用程序,在这个游戏当中,每位用户都可以控制两组军队,Group1andGroup2。你要创建一个标题为团队的高级菜单,在这个菜单下面创建两个子菜单:一个是叫作group1的子菜单,它的标题是group1;另一个是叫作group2的子菜单,它的标题是group2。当用户查找这个组菜单的时候,那两个子菜单就会被显示。用户一次只能查找一个军队,你必须确保一个团队能够被找到通过点击适当的子菜单或者是按ALT键加1或者2。同时你也要确保当前团队的查找能通过相应的子菜单项目的一个点被简要地说明。你不想改变任何你菜单项目的标题文本(内容),你需要选择下列的哪四种的做法?()A设置group1Submenu.Text属性为:Group&1设置group2Submenu.Text属性为:Group&2B设置Group1.ShortCut属性为:ALT1设置Group2.ShortCut属性为:ALT2C在group1Submenu.Click even事件中,在代码设置器中设置group1Submenu.Default Item属性为true在group2Submenu.Click even事件中,在代码设置器中设置group2Submenu.Default Item属性为trueD在group1Submenu.Click even事件中,在代码设置器中设置group2Submenu.Default Item属性为false在group2Submenu.Click even事件中,在代码设置器中设置group1Submenu.Default Item属性为falseE在group1Submenu.Click even事件中,在代码设置器中设置group1Submenu.Checked属性为true在group2Submenu.Click even事件中,在代码设置器中设置group2Submenu.Checked属性为trueF在group1Submenu.Click even事件中,在代码设置器中设置group2Submenu.Checked属性为false在group2Submenu.Click even事件中,在代码设置器中设置group1Submenu.Checked属性为falseG设置group1Submenu.RadioCheck属性为true设置group2Submenu.RadioCheck属性为trueH设置group1Submenu.RadioCheck属性为false设置group2Submenu.RadioCheck属性为false正确答案:B,E,F,G解析:暂无解析

考题 Which of the following statements are true when creating NETBIOS names? ()A、 NETBIOS names can only use alphanumeric characters.B、 You can use a ’.’ in a NETBIOS name.C、 You can use an ’_’ (underscore) in a NETBIOS name.D、 NETBIOS names must be UPPERCASEE、 NETBIOS names can be a maximum of 32 characters正确答案:B,C

考题 You need to display the last names of those employees who have the letter "A" as the second character in their names. Which SQL statement displays the required results? ()A、SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';B、SELECT last_name FROM EMP WHERE last name ='*A%'C、SELECT last_name FROM EMP WHERE last name ='_A%';D、SELECT last_name FROM EMP WHERE last name LIKE '*A%'正确答案:A

考题 Your network consists of a single Active Directory domain. The domain contains more than 300 group objects. The group objects are divided between several regional organizational units (OUs). You need to create a list of all groups that have names that begin with the word Sales. Which command should you use? ()A、Dsget groupB、Dsquery groupC、Netdom queryD、Net group正确答案:B

考题 You are the network administrator for TestKing.com. All user accounts and groups in the domain are in the container named Users. Company naming conventions require that names of global groups begin with G_ and names of domain local groups begin with DL_. A domain local group named HRServices does not meet the requirements. The HRServices group has one global group member named G_HRUsers. The HRServices group is assigned to Allow - Full Control permission for a shared folder named HRFiles. The shard folder is located on a file server. You need to rename the HRServices group to meet the naming convention requirements. In addition, you need to ensure that user access to the HRFiles shared folder is not disrupted while you perform the procedure. What are two possible ways to achieve this goal? ()(Each correct answer presents a cplete solution. Choose two.)A、Open Active Directory Users and Computers, and then delete the existing HRServices domain local group. Create a new domain local group named DL_HRServices. Add the G_HRUsers group to the DL_HRServices group. Assign the DL_HRServices group the Allow - Full Control permission for the HRFiles shared folder.B、Open the Active Directory Users and Computers, and then change the name of the HRservices group to DL_HRServices.C、Run the following command: dsadd group CN=DL_HRServices,CN=Users,DC=testking.com,DC=com - member CN=G_HRUsers,CN=Users,DC=testking,DC=comD、Run the following command: dsmove CN=HRServices,CN=Users,DC=testking,DC=com -newname DL_HRServices正确答案:B,D

考题 阅读以下说明和Java代码,将应填入(n)处的字句写在对应栏内。[说明]在一些大型系统中,大多数的功能在初始化时要花费很多时间,如果在启动的时候,所有功能(连不用的功能)都要全面初始化的话,会连带影响到应用软件要花很多时间才能启动。因此常将程序设计成到了实际要使用某种功能的阶段才初始化该功能。以下示例展示了Proxy(代理)模式,PrinterProxy类执行一些比较“轻”的方法——设置名称和取得名称,需要真正执行“重”的方法——真正打印——时才初始Print类。图6-1显示了各个类间的关系。[图6-1][Java代码]//Printable.JavapubliC (1) Printable{public abstract void setPrinterName(String name);public abstract String getprinterName();public abstract void print(String string);}//Printer.Javapublic class Printer implements Printable{private String name;public Printer(){System.out.println("正在产生Printer的对象实例");}public Printer(String name){this.name=name;heavyJob("正在产生Printer的对象实例("+name+")");public void setPrinterName(String name){this.name=name;public String getPrinterName(){return name;public void print(String string){System.out.println("===" +name+" ====");System.out.println(string);}}//PrinterProxy.Javapublic class PrinterProxy (2) Printable{private String name;private Printer real;public PrinterProxy(){}public PrinterProxy(String name){this.name=name;}public gynchronized void setPrinterName(String name){if( (3) ){real.setPrinterName(name);}this.name=name;}public String getprinterName(){return name;}public void print(String string){(4);real.print(string);}private synchronized void realize(){//产生真正的Printer对象if(real==null){real=(5);}}}(1)正确答案:interfaceinterface

考题 以下关于ContentResolver的说法错误的是()A、当外部应用需要对ContentProvider中的数据进行添加、删除、修改和查询操作时,可以使用ContentResolver类来完成。B、ContentResolver类提供了与ContentProvider类相同签名的insert、delete、update方法,但是没有提供query方法。C、通过ContentResolver对ContentProvider中的数据进行操作的时候,当需要将id为1时记录的name字段值更改为csg的时候,使用ContentValues的put方法,put("name","csg")。D、要获取ContentResolver对象,可以使用Activity提供的getContentResolver()方法。正确答案:B