Lifeboats are numbered（）.Odd numbers to starboard and even n

Your vessel has lifeboats on both sides. Lifeboat No. 2 is located ________.

A.forward of lifeboat No. 4 on the starboard side

B.forward of lifeboat No. 4 on the port side

C.aft of lifeboat No. 1 on the starboard side

D.All of the above

函数ReadDat()实现从文件IN.dat中读取1000个十进制整数到数组xx中；请编写函数 Compute()分别计算出数组xx中奇数的个数odd、偶数的个数even，以及所有数的平均值aver和方差totfc的值。最后调用函数WriteDat()，把结果输出到OUT. dat文件中。

计算方差的公式如下：

原始数据文件存放的格式是：每行存放10个数(每个数均大于0且小于等于2000)，并用逗号隔开。

注意：部分源程序已经给出。请勿改动主函数main()、读函数ReadDat()和输出数据函数 WriteDat()的内容。

include ＜stdio. h＞

include ＜stdlib. h＞

include ＜string. h＞

define MAX 1000

int xx[MAX], odd = 0, even = 0;

double aver = 0.0, totfc = 0.0;

void WriteDat(void);

int ReadDat(void)

{ FILE *fp;

int i, j;

if ((fp = fopen("IN. dat", "r")) == NULL)

return 1;

for (i=0; i＜100; i++)

{ for (j=0; j＜10; j++)

fscanf(fp, "%d,", &xx[i*10+j]);

fscanf(fp, "\n");

if (feof(fp))

break;

}

fclose(fp);

return 0;

}

void Compute(void)

{

}

void main ()

{ int i;

for (i=0; i＜MAX; i++)

xx[i] = 0;

if (ReadDat())

{

printf (" 数据文件 IN. dar 不能打开! \007\n");

return;

}

Compute ( );

printf("odd=%d\neven=%d\naver=%f\ntotfc=%f\n", odd, even, aver, totfc);

WriteDat ();

}

void WriteDat(void)

{ FILE *fp;

fp = fopen("OUT.dat", "w");

fprintf(fp, "%d\n%d\n%f\n%f\n", odd, even, aver, totfc);

fclose (fp);

}

对输入一个整数进行判断，若是偶数，输出even，否则输出odd，在子函数fun2功能是判定整数是否为偶数，若是偶数，返回1，否则返回0int fun2(int x){if(x%2==0)；return 0;}main(){int n;scanf("%d",&n);ifprintf("even\n");else printf(odd\n");}

Lifeboats are numbered ______.Odd numbers to starboard and even numbers to port．

A.from forward to aft

B.from aft to forward

C.at master's option

D.as per owner's instruction

A.Compilationfails.

B.“odd”willalwaysbeoutput.

C.“even”willalwaysbeoutput.

D.“odd”willbeoutputforoddvaluesofx，and“even”forevenvalues.

E.“even”willbeoutputforaddvaluesofx，and“odd”forevenvalues.

请编制函数ReadDat()实现从文件IN93.DAT中读取1000个十进制整数到数组xx中。请编制函数 Compute()分别计算出xx中奇数的个数odd、偶数的个数even、平均值aver及方差totfc的值，最后调用函数WriteDat()把结果输出到OUT93.DAT文件中。

计算方差的公式如下：

原始数据的存放格式是：每行存放10个数，并用逗号隔开(每个数均大于0且小于等于2000)。

注意：部分源程序已给出。

请勿改动主函数main()和写函数WriteDat()的内容。

试题程序：

include＜stdio.h＞

include＜stdlib.h＞

include＜string.h＞

define MAX 1000

int xx[MAX],odd=0,even=0;

double aver=0.0,totfc=0.0;

void WriteDat(void);

int ReadDat(void)

{

FILE *fp;

if((fp=fopen("IN93.DAT","r"))==NULL

return 1;

fclose(fp);

return O;

}

void Compute(void)

{

}

void main( )

{

int i;

for(i=O;i＜MAX;i++)

xx[i] =0;

if (ReadDat ( ) )

{

print f ("数据文件IN93.DAT不能打开! \007\n");

return;

}

Compute();

printf( "ODD=%d\nEVEN=%d\nAVER=%lf\nTOTFC=%lf\n",

odd, even,aver,totfc);

WriteDat();

}

void WriteDat(void)

{

FILE *fp;

int i;

fp=fopen("OUT93.DAT","w");

fprintf(fp,"%dln%dln%lf\n%lfkn",odd,even,aver,totfc);

fclose(fp);

}

Preferred channel buoys indicate the preferred channel to transit by ______.

A.odd or even numbers

B.the color of their top band

C.the location of the buoy in the channel junction

D.the buoy’s light rhythms