在计划网络图中,节点i的最迟时间TL(i)是指()
第1题:
阅读程序: Sub p( b () As Integer)For i =1To 4 b(i) = 2(iNext i End Sub Private Sub Command1_Click()Dim a (1 To 4) As Integer a(1)=5 a(2)=6 a(3)=7 a(4)=8 call p (a) For i=1 To 4 Print a(i) Next iEnd Sub运行上面的程序,单击命令按钮,输出结果为。
第2题:
下面程序的输出结果是【 】。
Private Sub Form_Click()
i=0
Do Until 0
i=i+1
if i>10 then Exit Do
Loop
Print i
End Sub
第3题:
下面程序段的运行结果是【 】。
Option Base 1
Private Sub swap(a()As InteSer)
For I=1 to 10\2
t=a(i)
a(i)=a(10-1+1)
a(10-1+1)=t
Next1
End Sub
Private Sub Form_Click()
Dim x(10)As Integer
For I=1 to 10
x(i)=I*2
Next1
Swap x()
For1=1 to 10
Print x (i)
Next I
End Sub
第4题:
有如下事件过程:
Private Sub Form. Active ( )
Dim Score (1 to 3) As Integer
Dim i As Integer
Dim t As Variant
Fori=3 To 1 step-1
Score (i) = 2 * i
Next
For Each t In Score
Print t
Next
End Sub
程序运行后窗体上显示的值为【 】。
第5题:
以下能够正确计算n!的程序是
A.Private Sub Command1 Click() n=5:x=1 Do x=x * I I=I + 1 Loop While I < n Print x End Sub
B.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X*I I=I + 1 Loop While I <n Print x End Sub
C.Private Sub Command1_Click() n=5:X=1:I=1 Do X=X * I I=I + 1 Loop While I<=n Print X End Sub
D.Private Sub Command1_Click() n=5:X=1:I=1 Do x=x * I I=I + 1 Loop While I>n Print X End Sub
第6题:
下面程序段的运行结果是【 】。
Option Base 1
Private Sub Swap (a() As Integ
For I=1 to 10\2
t=a(I)
a(I)=a(10-I+1)
a(10-I+1)=t
Next I
End Sub
Private Sub Form_Click()
Dim x(10) As Integer
For I=1 to 10
x(I)=I*2
Next I
Swap x()
For I=1 to 10
Print x(I)
Next I
End Sub
第7题:
以下能够正确计算n!的程序是
A.Private Sub Command1_Chck( ) n=5:x=1 Do x=x*i i=i+1 Loop While i<n Print x End Sub
B.Private Sub Command1_Click( ) n=5:x=1:i=l Do x=x*i i=i+1 Loop While i<n Print x End Sub
C.Private Sub Command1_Click( ) n=5:x=1:i=l Do x=x*i i=i+1 Loop While i<=n Print x End Sub
D.Private Sub Command1_Click( ) n=5:x=1:i=l Dox=x*i i=i+1 Loop While i>n Print x End Sub
第8题:
程序执行结果s的值是【 】.
Private Sub Command l-Click ()
I =0
Do
S= I +S
I = I + l
Loop Until I >=4
End Sub
第9题:
以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }
A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4
B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18
C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4
D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18
第10题:
下面程序段,运行后的结果是 Private Sub Commandl_Click( ) Dim b%(1 To 4),i%,t# For i=1 To 4 b(i)=i Next i t=Tof(b( ) ) Print"t=";t, End Sub Function Tof(a() As Integer) Dim t#,i% t=1 For i=2 To UBound(A)t=t * a(i) Next i Tof=t End Function
A.t=18
B.t=24
C.t=30
D.t=32