Routers R1, R2, R3, and R4 connect to the same 10.10.10.0/24

题目
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Routers R1, R2, R3, and R4 connect to the same 10.10.10.0/24 LAN- based subnet. OSPF is fully working in the subnet. Later, R5, whose OSPF priority is higher than the other four routers, joins the subnet. Which of the following are true about the OSPF database exchange process over this subnet at this point?()
A

R5 will send its DD, LSR, and LSU packets to the 224.0.0.5 all - DR - routers multicast address.

B

R5 will send its DD, LSR, and LSU pack ets to the 224.0.0.6 all - DR - routers multicast address.

C

The DR will inform R5 about LSAs by sending its DD, LSR, and LSU packets to the 224.0.0.6 all- SPF - routers multicast address.

D

The DR will inform R5 about LSAs by sending its DD, LSR, and LSU pa ckets to the 224.0.0.5 all- SPF - routers multicast address.

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相似问题和答案

第1题:

在电阻应变仪的全桥电路中,R1、R2、R3、和R4按顺时针排列,当()时,即可起到温度补偿的作用。

A、R1和R2为测量工作应变片,R3和R4为温度补偿应变片

B、R1和R3为测量工作应变片,R2和R4为温度补偿应变片

C、R1和R4为测量工作应变片,R2和R3为温度补偿应变片

D、R2和R3为测量工作应变片,R1和R4为温度补偿应变片


参考答案:B

第2题:

Refer to the exhibit. Autonomous systems 200 and 300 have EBGP sessions established with their directly connected routers in au tonomous system 100. IGP has been configured on all routers in autonomous system 100 and they successfully exchange routing updates. Traffic originated in autonomous system 200 cannot reach the destination autonomous system 300. What configuration shoul d be done on the routers in autonomous system 100 in order for the traffic coming from autonomous system 200 to be forwarded to autonomous system 300?()

A. IBGP session must be established between routers R1 R2 and R2 R3, and the synchronization must be turned off.

B. IBGP speakers within autonomous 100 must be fully meshed, and the synchronization must be turned on.

C. IBGP session must be established between routers R1 R2 and R2 R3, and the synchronization must be turned on.

D. IBGP session mu st be established between routers R1 and R3, and the synchronization must be turned off.

E. IBGP speakers within autonomous 100 must be fully meshed, and the synchronization must be turned off.

F. IBGP session must be established between routers R1 and R3, and the synchronization must be turned on.


参考答案:E

第3题:

电桥相邻两臂称为相邻臂(如R1与R2,R3与R4),相对两臂成为相对臂(如R1与R4,R2与R3)。当满足()时,电桥处于平衡状态。


本题答案:R1R4-R2R3=0

第4题:

?某计算机系统中共有3个进程P1、P2和P3,4类资源r1、r2、r3和r4。其中r1和r3每类资源只有1个实例,r2资源有2个实例,r4有3个实例。 当前的资源分配状态如下:

E={<P1,r1>,<P2,r3>,<r2,P1>,<r1,P2>,<r2,P2>,<r3,P3>}

若进程P3申请一个r2类资源,则系统可能会发生下列哪一种现象?

A.A.死锁

B.B.无死锁

C.C.活锁

D.D.饥饿


正确答案:A

第5题:

Refer to the exhibit. EIGRP is configured with the default configuration on all routers. Auto summariz ation is enabled on routers R2 and R3, but it is disabled on router R1.Which two EIGRP routes will be seen in the routing table of router R3?()

A. 10.0.0.0/8

B. 172.16.10.0/24

C. 172.16.0.0/24

D. 10.10.10.0/24

E. 172.16.0.0/16

F. 10.10.0.0/16


参考答案:D, E

第6题:

Given the network diagram, which routers currently make up the IS - IS backbone?()

A. R3,R4,R6

B. R2,R3,R6,R7

C. R1 through R8

D. R3,R4,R5,R6

E. R2,R3,R4,R6,R7


参考答案:E

第7题:

Refer to the exhibit. On the basis of the configuration that is provided, how would the BGP updates that come from router R1 be replicated inside autonomous system 65200?()

A. All BGP updates that are received on router R 2 will be sent to routers R3 and R4. Routers R3 and R4 will then forward those BGP updates to router R5

B. None of the BGP updates that are received on router R2 will ever be received by router R5

C. All BGP updates that are received on router R2 will not be sent to routers R3 and R4

D. All BGP updates that are received on router R2 will be sent directly to router R5


参考答案:B

第8题:

有一直流电桥电路如下图,其电桥的平衡条件是()。

A、R1²R2=R3²R4

B、R1²R3=R2²R4

C、R1²R4=R2²R3


参考答案:C

第9题:

R1(AS1)------R2(AS2)-----R3(AS2)----R4(AS2),R1在AS1,R2,R3,R4在AS2,R1和R2建EBGP,R2和R3IBGP,R3和R4IBGP,产生BGP路由从R1传给R2,问这条路有会不会在R4上出现,如果不会,怎么解决.


No,R4willnothavetheroute.
Therearethreewaystoresolvethisproblem:
Firstone:full-meshed
Secondone:Route-reflector

第10题:

如图D-9所示,R1=R2=R3=R4,求等效电阻R。


答案:
解析:
解:图(a)的等效电路为图(b),由图(b)可得
R5=R1×R2/(R1+R2)+R3=(3/2)R1
R=R5×R4/(R5+R4)=3/5R1
答:等效电阻R为3/5R1。

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