A customer is acquiring a new I

阅读下列说明和C++代码，填补代码中的空缺，将解答填入答题纸的对应栏内。 【说明】 以下C++代码实现一个简单客户关系管理系统（CrM）中通过工厂（Customerfactory）对象来创建客户（Customer）对象的功能。客户分为创建成功的客户（realCustomer）和空客户（NullCustomer）。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图6-1所示。图6-1

【C++代码】 include<iostream> include<string> using namespace std; class Customer｛ protected: string name; public: （ 1 ） boll isNil()=0; （ 2 ） string getName()=0; ﹜; class RealCustomer ( 3 )｛ Public: realCustomer(string name)｛this->name=name;﹜ bool isNil()｛ return false; ﹜ string getName()｛ return name; ﹜ ﹜; class NullCustomer ( 4 ) ｛ public: bool isNil()｛ return true; ﹜ string getName()｛ return 〝Not Available in Customer Database〞; ﹜ ﹜; class Customerfactory｛ public: string names［3］=｛〝rob〞, 〝Joe〞,〝Julie〞﹜; public: Customer*getCustomer(string name)｛ for （int i=0;i<3;i++)｛ if （names[i].( 5 ) )｛ return new realCustomer(name); ﹜ ﹜ return ( 6 ); ﹜ ﹜; class CRM｛ public: void getCustomer()｛ Customerfactory*( 7 ); Customer*customer1=cf->getCustomer(〝Rob〞); Customer*customer2=cf->getCustomer(〝Bob〞); Customer*customer3=cf->getCustomer(〝Julie〞); Customer*customer4=cf->getCustomer(〝Laura〞); cout<<〝Customers〞<<endl; cout<<Customer1->getName()<<endl; delete customer1; cout<<Customer2->getName()<<endl; delete customer2; cout<<Customer3->getName()<<endl; delete customer3; cout<<Customer4->getName()<<endl; delete customer4; delete cf; ﹜ ﹜; int main()｛ CRM*crs=new CRM(); crs->getCustomer(); delete crs; return 0; ﹜ /*程序输出为： Customers rob Not Available in Customer Database Julie Not Available in Customer Database */

请完成下列Java程序：假设某家银行，它可接受顾客的汇款，每做一次汇款，便可计算出汇款的总额。现有两个顾客，每人都分3次，每次50元将钱汇入。编写一个程序，模拟实际作业。要求实现2个类，一个是银行类，一个是顾客类。

注意：请勿改动main()主方法和其他已有语句内容，仅在下划线处填入适当的语句。

程序运行结果如下：

Customer2 :sum= 50

Customer1 :sum= 50

Customer1 :sum= 100

Customer2 :sum= 100

Customer1 :sum= 150

Customer2 :sum= 150

class bank{

private static int sum=0;

public static void add(int.n,char c){

int tmp=sum;

______________;

try{

Thread.sleep(((int) ((2000-500+1)*(Math.random())))+500);

}

catch(InterruptedException e){}

sum=tmp;

System.out.println("Customer"+c+" :sum= "+sum);

}

}

class customer extends Thread{

static char flag17_2 = '1';

public void run(){

char myflag17_2;

synchronized(this) {

myflag17_2 = flag17_2++;

}

for(int i=1;i＜=3;i++)

______________________;

}

}

public class ex17_2{

public static void main(String args[]){

customer c1=new customer();

customer c2=new customer();

c1.start();

c2.start();

}

}

阅读以下说明和 Java程序，填补代码中的空缺，将解答填入答题纸的对应栏内。 【说明】 以下Java代码实现一个简单客户关系管理系统（CRM）中通过工厂（CustomerFactory ）对象来创建客户（Customer）对象的功能。客户分为创建成功的客户（RealCustomer）和空客户 （NullCustomer）。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图 5-1 所示。图5-1 类图

【Java代码】 Abstract class Customer﹛ Protected String name; （ 1 ）boolean isNil(); （ 2 ）String getName(); ﹜ Class RealCustomer （ 3 ）Customer{ Public RealCustomer(String name){ this.name=name; } Public String getName(){ return name ; } Public boolean is Nil() { return false; } ﹜ Class NullCustomer（ 4 ）Customer﹛ Public String getName()﹛ return "Not Available in Customer Database"; ﹜ Public boolean isNil() ﹛ return true; ﹜ ﹜ class Customerfactory { public String[] names = {"Rob"，"Joe"，"Julie"}; public Customer getCustomer(String name) { for (int i = 0; i < names.length;i++) { if (names[i].（ 5 ）)﹛ return new RealCustomer(name); ﹜ ﹜ return （ 6 ）; ﹜ ﹜ Public class CrM﹛ Public viod get Customer()﹛ Customerfactory（ 7 ）; Customer customer1-cf.getCustomer("Rob"); Customer customer2=cf.getCustomer("Bob"); Customer customer3= cf.getCustomer("Julie"); Customer customer4= cf.getCustomer("Laura"); System.out.println("customers”) System.out.println(customer1.getName()); System.out.println(customer2getName()); System.out.println(customer3.getName()); System.out.println(customer4.getName()); ﹜ Public static viod main (String[]arge)﹛ CRM crm =new CRM(); Crm.getCustomer(); ﹜ ﹜ /*程序输出为： Customers rob Not Available in Customer Database Julie Not Available in Customer Database */

A.a new one

B.an new one

C.the new one

D.one new