第1题:
下列程序执行后的输出结果是
#included<string.h>
main( )
{ char arr[2][4];
strcpy(arr,"you");strepy(arr[1],"me");
arr[0][3]='&';
cout<<arr<<endl;
}
A.you&me
B.you
C.me
D.err
第2题:
A.howdoyoudo!
B.how
C.howdoyoudo
D.hdyd
第3题:
A.how-are-yous
B.of how-are-you’s
C.how-are-you’s
D.of how are you
第4题:
Me,you是两个初始集合,则下列关于派生集合定义方式正确的是
A.link/me,you/:a;
B.link(me,you):a;
C.link/me you/a;
D.link(me,you)/a;
第5题:
2.—How _______you?
—I_______ fine, thanks.
A.are;is
B.are; am
C.are;are
D.is,am
第6题:
A、must misunderstand
B、must have misunderstood
C、must be misunderstanding
D、had to misunderstand
第7题:
Jerry: I've been back from a business trip.
Bob: ______
A、It's very nice of you.
B、How's everything going?
C、You're kind to say so.
D、I'd love to.
第8题:
you, do, eraser, how, spell【连词成句)
________________________?
第9题:
49.—What about some drinks?
—__________.
A. Help, yourself
B. Good idea
C. You're welcome
D. Me,too
第10题:
me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是
A.ps(me,you):c;
B.ps(you,me):c;
C.ps(a,b):c;
D.ps(b,a):c;