_Left
Left_
Left
eft
第1题:
下面可以正确定义两个整型变量和—个字符串变量的语句是______。
A.Dim n,m As Integer,s As String
B.Dim a%,b$,c As String
C.Dim a As Integer,b,c As String
D.Dim x%,y As Integer,z As String
第2题:
假设有如下的记录类型: Type Student number As String name AS String age As Integer End Type 则正确引用该记录类型变量的代码是______。
A.Student. name="" s. name="张红"
B.Dim s As Student s. Dame="张红"
C.Dim s As Type Student s. name="张红"
D.Dim s As Type s. name="张红"
第3题:
A、hon
B、ho
C、on
D、ngq
答案:C
解析:此题主要是讲substring的用法,substring是截取(提取)字符,substring(start,end)start为开始索引,end为结束索引,但不包括end。
此题的起始位置索引为下标为2的字符,结束索引为下标为4 的字符。字符串s1=“Chongqing”,下标从0开始,相对应的下标为0的字符是C,依次往后推,到下标为2 时,也是起始位置,对应的字符为o,结束下标为4,但是并不包括下标为4的字符,所以截取到下标为3的字符,也就是n。所以答案是on。
第4题:
下面这段代码中,变量myInteger的结果是()。 Dim myString As String="ABCDE" Dim myInteger As Integer myInteger=myString.IndexOf("D")
第5题:
设有如下的记录类型: TypeStudent number As String name AS String age As Integer End Type 则正确引用该记录类型变量的代码是( )。
A.Student.name="张红"
B.Dim s As Student s.name="张红"
C.Dim s As Type Student s.name="张红"
D.Dim s As Type s.name="张红"
第6题:
( 11 )下面可以正确定义 2 个整形变量和 1 个字符串变量的语句的是( )
A ) Dim n,m AS Interger,s AS String
B ) Dim a%,b$,c AS String
C ) Dim a AS Integer,b,c AS String
D ) Dim x%,y AS Integer,z AS String
第7题:
第8题:
下面可以正确定义2个整形变量和1个字符串变量的语句的是( )。
A.Dim n,m AS Interger,s AS String
B.Dim a%,b$,c AS String
C.Dim a AS Integer,b,c AS String
D.Dim x%,y AS Integer,z AS String
第9题:
下述代码A和B正确的值是() Dim X As String = "123" Dim Y As Integer = 123 Dim A As String = X + Y Dim B As String = X & Y
A“246”,“123123”
B246,“123123”
C“123123”,“123123”
D123123,“123123”
第10题:
下面这段代码中,变量myChar的结果是()。 Dim myString As String="ABCDE" Dim myChar As Char myChar=myString.Chars(3)