单选题public class Foo {  public void main （String [] args）   {  system.out.printIn（“Hello World.”）； } }  What is the result？（）A  An exception is thrown.B  The code does no compile.C  “Hello World.” Is printed to the terminal.D  The program exits without pri

第1题：

public class Test {   public static void main （String args） {  string foo = “blue”；  string bar = foo；   foo = “green”；   System.out.printIn（bar）；   }   }   What is the result？（）  

• A、 An exception is thrown.
• B、 The code will not compile.
• C、 The program prints “null”
• D、 The program prints “blue”
• E、 The program prints “green”

第2题：

public class Foo {  public void main（ String[] args ） {  System.out.println（ “Hello” + args[0] ）；  }  }   What is the result if this code is executed with the command line？（）

• A、 Hello
• B、 Hello Foo
• C、 Hello world
• D、 Compilation fails.
• E、 The code does not run.

第3题：

public class foo {   public static void main （Stringargs） {  String s；   system.out.printIn （“s=” + s）；   }   }   What is the result？（）

• A、 The code compiles and “s=” is printed.
• B、 The code compiles and “s=null” is printed.
• C、 The code does not compile because string s is not initialized.
• D、 The code does not compile because string s cannot be referenced.
• E、 The code compiles， but a NullPointerException is thrown when toString is called.

第4题：

public class foo {  public static void main （String[]args） {  String s；  system.out.printIn （“s=” + s）；  }  }   What is the result？（）  

• A、 The code compiles and “s=” is printed.
• B、 The code compiles and “s=null” is printed.
• C、 The code does not compile because string s is not initialized.
• D、 The code does not compile because string s cannot be referenced.
• E、 The code compiles， but a NullPointerException is thrown when toString is called.

第5题：

class A {  public A（） {  System.out.println（“hello from a”）；  }  }  class B extends A {  public B （） {  System.out.println（“hello from b”）；  super（）；  }  }  public class Test {  public static void main（String args[]） {  A a = new B（）；  }  }   What is the result when main is executed？（）  

• A、 Compilation fails.
• B、 hello from a
• C、 hello from b
• D、 hello from b hello from a
• E、 hello from a hello from b

第6题：

public class Foo {   public void main （String args） {   system.out.printIn（“Hello World.”）；   }   }   What is the result？ （） 

• A、 An exception is thrown.
• B、 The code does no compile.
• C、 “Hello World.” Is printed to the terminal.
• D、 The program exits without printing anything.

第7题：

public class foo {   public static void main （stringargs）   try {return；}   finally {system.out.printIn（“Finally”）；}   }     What is the result？（）  

• A、 The program runs and prints nothing.
• B、 The program runs and prints “Finally”
• C、 The code compiles， but an exception is thrown at runtime.
• D、 The code will not compile because the catch block is missing.

第8题：

public class Foo implements Runnable （  public void run （Thread t） {  system.out.printIn（“Running.”）；  }  public static void main （String[] args）  {  new thread （new Foo（））.start（）；  } ）   What is the result？（）      

• A、 An exception is thrown.
• B、 The program exists without printing anything.
• C、 An error at line 1 causes compilation to fail.
• D、 An error at line 2 causes the compilation to fail.
• E、 “Running” is printed and the program exits.

第9题：

public class foo {  public static void main （string[]args）  try {return；}  finally {system.out.printIn（“Finally”）；}  }  What is the result？（）

• A、 The program runs and prints nothing.
• B、 The program runs and prints “Finally”
• C、 The code compiles， but an exception is thrown at runtime.
• D、 The code will not compile because the catch block is missing.

第10题：

public class foo {  static String s；  public static void main （String[]args） {  system.out.printIn （“s=” + s）；  } }  What is the result？（）  

• A、 The code compiles and “s=” is printed.
• B、 The code compiles and “s=null” is printed.
• C、 The code does not compile because string s is not initialized.
• D、 The code does not compile because string s cannot be referenced.
• E、 The code compiles， but a NullPointerException is thrown when toString is called.