R1 is internal to area 1, and R2 is internal to area 2. Subn

题目
单选题
R1 is internal to area 1, and R2 is internal to area 2. Subnet 10.1.1.0/24 exists in area 2 as a connected subnet off R2. ABR ABR1 connects area 1 to backbone area 0, and ABR2 c onnects area 0 to area 2. Which of the following LSAs must R1 use when calculating R1's best route for 10.1.1.0/24?()
A

R2's Type 1 LSA

B

Subnet 10.1.1.0/24's Type 2 LSA

C

ABR1's Type 1 LSA in area 0

D

Subnet 10.1.1.0/24's Type 3 LSA in Area 0

E

  Subnet 10.1.1.0/24's Type 3 LSA in Area 1

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相似问题和答案

第1题:

阅读以下说明,回答问题1和问题2,将解答填入答题纸对应的解答栏内。 【说明】 某公司有3个分支机构,网络拓扑结构及地址分配如图4-1所示。

【问题1】(每空1分,共11分) 公司申请到202.111.1.0/29的公有地址段,采用NAPT技术实现公司内部访问互联网的要求,其中,192.168.16.0/22网段禁止访问互联网。 R1、R2和R3的基本配置已正确配置完成,其中R1的配置如下。请根据拓扑结构,完成下列配置代码。 R1的基本配置及NAPT配置如下: R1>enable Rlconfig tenrunal R1(config)interface fastenthemet 0/0 R1(config-if)ip address 192.168.0.1 255.255.255.252 R1(config-if)no shutdown Rl(config-if)exit R1(config)interface fastenthemet 0/1 R1(config-if)ip address 192.168.0.9 255.255.255.252 R1(config-if)no shutdown R1(config-if)exit R1(config)interface fastenthernet 0/2 R1(config-if)ip address (1) 255.255.252.0 //使用网段中最后一个地址 R1(config-if)no shutdown R1(config-if)exit R1(config)interface serial 0 R1(config-if)ip address 202.111.1.1 255.255.255.248 R1(config-if)no shutdown R1(corffig)ip nat pool ss 202.111.1.1 (2) netmask (3) R1(corffig) interface (4) fastenthernet 0/0-1 R1(config-if)ip nat (5) R1(config-if)interface serial 0 Rl(config-if)ip nat (6) R1(config-if)exit R1(config)access-Iist l permit 192.168.0.0 (7) Rl(config)ip nat inside (8) list (9) pool (10) (11) 【问题2】.(每空2分,共4分) 在R1、R2和R3之间运行OSPF路由协议,其中R1、R2和R3的配置如下。 行号 配置代码 1 R1(config)router ospf 1 2 R1(config-router)network 192.168.4.0 0.0.3.255 area 0 3 Rl(config-router)network 192.168.0.0 0.0.0.3 area 0 4 Rl(config-router)network 192.168.0.8 0.0.0.3 area 0 5 R2>enable 6 R2config terminal 7 R2(config)router ospf 2 8 R2(config-router)netvrork 192.168.8.0 0.0.3.255 area 0 9 R2 (config-router)network 192.168.12.0 0.0.3.255 area 0 1 0 R2 (config-router)network 192.168.0.4 00.0.3 area 0 1 1 R3>enable 1 2 R3config terminal 1 3 R3(config)router ospf 3 1 4 R3(config-router)netvrork 192168.0.8 00.0.3 area 0 1 5 R3(config-router)network 192.168.0.4 0.0.0.3 area 0 1.配置完成后,在R1和R2上均无法ping通R3的局域网,可能的原因是(12)。 (12)备选答案: A.在R3上未宣告局域网路由 B.以上配置中第7行和第13行配置错误 C.第1行配置错误 D.R1、R2未宣告直连路由. 2.在OSPF中重分布默认路由的命令是:(13)。 (13)备选答案: A.Rldefault-informaton originate B.R1(config-if)default-information originate C.R1(config-router)default-information originate D.Rl(config)default-information originate


正确答案:【问题1】(每空1分,共11分)
(1)192.168.7.254
(2)202.111.1.6
(3)255.255.255.248
(4)range
(5)inside
(6)outside
(7)0.0.15.255
(8)source
(9)1
(10)ss
(11)overload
【问题2】(每空2分、共4分)
(12)A
(13)C

第2题:

Which of the following is true about routers internal to a totally NSSA area?()

A. Routers cannot redistribute external routes into the area.

B. Routers should have zero Type 3 LSAs in their LSDBs.

C. Routers should have zero Type 5 LSAs in their LSDBs.

D. Routers should learn default routes from the ABRs attached to the area.


参考答案:C, D

第3题:

路由器R1的拓扑连接和地址分配如下图所示,如果在R1上安装OSPF协议,运行命令:router ospf 200,则配置E0和E1端口的命令分别是______。

A.network 10.1.1.0 255.255.255.0 area 0 network 192.168.1.0 255.255.255.0 area 1

B.network 10.1.1.1 255.255.255.0 area 0 network 192.168.1.1 255.255.255.0 area 1

C.network 10.1.1.255 0.0.0.8 area 0 network 192.168.1.255 0.0.0.8 area 1

D.network 10.1.1.0 0.0.0.255 area 0.0.0.0 network 192.168.1.0 0.0.0.255 area 1


正确答案:D
解析:在OSPF配置模式下,使用:“network ip子网号>wild-card-mask>area区域号>”。命令定义参与OSPF的子网地址。题中EO端口的IP地址为10.1.1.1/24,则所属网络地址为10.1.1.0,子网掩码为255.255.255.0,为0.0.0.255;E1端口的IP地址为192.168.1.1/24,则所属网络地址为192.168.1.0,子网掩码为255.255.255.0,为0.0.0.255。

第4题:

路由器R1的拓扑连接和地址分配如图5-3所示,如果在R1上安装OSPF协议,运行命令router ospf 200,则配置E0和E1端口的命令分别是(26)。

A.network 10.1.1.0255.255.255.0 area0 network 192.168.1.0 255.255.255.0 area 1

B.network 10.1.1.1 255.255.255.0 area0 network 192.168.1.1 255.255.255.0 area 1

C.network 10.1.1.255 0.0.0.8 area 0 network 192.168.1.255 0.0.0.8 area 1

D.network 10.1.1.0 0.0.0.255 area 0.0.0.0 network 192.168.1.0 0.0.0.255 area 1


正确答案:D
解析:在如图5-3所示的网络拓扑结构中,在路由器R1上安装OSPF协议,运行router ospf200启用ID号为200的路由器进程,且进入路由协议的配置子模式。
  当配置OSPF协议时,指定与某一路由器相连的网络的配置命令是“network address wildcard-mask are area area-id”。其中,“address”字段是指与路由器相连的网段IP地址(注意不是该网段中某个具体的IP地址);“wildcard-mask”用于指明该网段IP地址的子网掩码的反码;网络区域ID(area-id)一般取数字0~4 294 967 295,也可以用类似于IP地址X.X.X.X的表达格式。当网络区域ID为0或0.0.0.0时,说明该网络区域为主干域。不同网络区域的路由器是通过主干域来获取路由信息的。
  由于路由器R1的e0端口的IP地址为10.1.1.1/24,该IP地址的网络地址为10.1.1.0,“/24”是子网掩码为255.255.255.0的缩写形式,而该子网掩码的反码是0.0.0.255。因此,指定与路由器R1的e0端口相连的网络的配置命令是network 10.1.1.00.0.0.255 area0.0.0.0。其中“0.0.0.0”表示该网段为主干域。
  同理,路由器R1的e1端口的IP地址为192.168.1.1/24,该IP地址的网络地址为192.168.1.0,子网掩码为255.255.255.0,该子网掩码的反码是0.0.0.255。因此,指定与路由器R1的e1端口相连的网络的配置命令足network 192.168.1.0 0.0.0.255 area 1。其中,10.1.1.0是e0所在端口的IP地址,0.0.0.255是 255.255.255.0的反向掩码。

第5题:

You are developing a verification plan for an upcoming OSPF implementation. Part of this plan is to verify the status of type 3 LSAs within the network. Which routers should you verify first to ensure that the configuration s are correct for generating type 3 LSAs?()

A. Internal routers within the backbone area (area 0)

B. Internal routers within the NSSAs

C. Internal routers within the stubby areas

D. ASBRs

E. ABRs

F. DRs and BDRs


参考答案:E

第6题:

ABR R1 has been configured with an area 1 stub no - summary command. Which stubby area type is area 1?()

A. Stub

B. Totally stubby

C. NSSA

D. Totally NSSA


参考答案:B

第7题:

The following output exists on Router R1, a router internal to area 1. What can you d etermine as true from the output of the show ip ospf database summary command?()

A. The LSA was created by an ABR due to an area range command.

B. The LSA was created by an ASBR due to a summary - address command.

C. If cr eated by an area range command, the best metric for a subordinate subnet on that ABR must have been 11.

D. None of the other answers is correct.


参考答案:D

第8题:

路由器R1的拓扑连接和地址分配如图1-9所示,如果在R1上安装OSPF协议,运行下列命令:router ospf 200,则配置E0和E1端口的命令分别是(40)。

A.network 10.1.1.0 255.255.255.0 area 0 network 192.168.1.0 255.255.255.0 area 1

B.network 10.1.1.1 255.255.255.0 area 0 network 192.168.1.1 255.255.255.0 area 1

C.network 10.1.1.255 0.0.0.8 area 0 network 192.168.1.255 0.0.0.8 area 1

D.network 10.1.1.0 0.0.0.255 area 0.0.0.0 network 192.168.1.0 0.0.0.255 area 1


正确答案:D
解析:在图1-9所示的网络拓扑结构中,在路由器R1上安装OSPF协议,运行routerospf200启用ID号为200的路由器进程,且进入路由协议的配置子模式。配置OSPF协议时,指定与某一路由器相连的网络的配置命令是“networkaddresswildcard-maskareaarea-id”。其中,“address”字段是指与路由器相连的网段IP地址(注意不是该网段中某个具体的IP地址);“wildcard-mask”用于指明该网段IP地址的子网掩码的反码;网络区域ID(area-id)一般取数字0~4294967295,也可以用类似IP地址x.x.x.x的表达格式。当网络区域ID为0或0.0.0.0时,说明该网络区域为主干域。不同网络区域的路由器是通过主干域来学习路由信息的。由于路由器R1的e0端口的IP地址为10.1.1.1/24,该IP地址的网络地址为10.1.1.0,“/24”是子网掩码为255.255.255.0的缩写形式,而该子网掩码的反码是0.0.0.255。因此,指定与路由器R1的e0端口相连的网络的配置命令是network10.1.1.00.0.0.255area0.0.0.0。其中“0.0.0.0”表示该网段为主干域。同理,路由器R1的e1端口的IP地址为192.168.1.1/24,该IP地址的网络地址为192.168.1.0,子网掩码为255.255.255.0,该子网掩码的反码是0.0.0.255。因此,指定与路由器R1的e1端口相连的网络的配置命令是network192.168.1.00.0.0.255area1。其中,10.1.1.0是e0所在端口的IP地址,0.0.0.255是255.255.255.0的反向掩码。

第9题:

Refer to the exhibit. OSPF is configured on all routers in the network. On the basis of the show ip ospf n eighbor output, what prevents R1 from establishing a full adjacency with R2? ()

A. Router R1 will only establish full adjacency with the DR and BDR on broadcast multi- access networks.

B. Router R2 has been elected as a DR for the broadcast multiaccess network in OSPF area 1.

C. Routers R1 and R2 are configured as stub routers for OSPF area 1 and OSPF area 2.

D. Router R1 and R2 are configured for a virtual link between OSPF area 1 and OSPF area 2.

E. The Hello parameters on routers R1 and R2 do not m atch.


参考答案:A

第10题:

Which of the following is an OSPF configuration parameter that is used on an ABR, but not on an internal router?()

  • A、A virtual link to area 0.
  • B、OSPF summarization command.
  • C、default - cost extension to the area command.
  • D、no - summary extension to the area stub comm and.
  • E、None of the other alternatives apply

正确答案:D

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