Evaluate these two SQL statements: SELECT last_name, salary

The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? （）

A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;

B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;

C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;

D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

Evaluate this SQL statement:SELECT ename, sal, 12* sal+100 FROM emp;The SAL column stores the monthly salary of the employee. Which change must be made to the abovesyntax to calculate the annual compensation as "monthly salary plus a monthly bonus of $100, multiplied by 12"? （）

A. No change is required to achieve the desired results.

B. SELECT ename, sal, 12* (sal+100) FROM emp;

C. SELECT ename, sal, (12* sal)+100 FROM emp;

D. SELECT ename, sal +100,*12 FROM emp;

A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);

B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);

C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);

D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);

E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);

F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

A. The two statements produce identical results.

B. The second statement returns a syntax error.

C. There is no need to specify DESC because the results are sorted in descending order by default.

D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns:LAST NAME VARCNAR2(35) NOT NULLSALARY NUMBER(9,2) NOT NULLCOMMISION_PCT NUMBER(4,2)Which statement ensures that a value is displayed in the calculated columns for all employees? （）

A. SELECT last_name, 12*salary* commission_pct FROM emp;

B. SELECT last_name, 12*salary* (commission_pct,0) FROM emp;

C. SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;

D. SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

A. 17000.00

B. 17000*****

C. ****170.00

D. **17000.00

E. an error statement

The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? （）

A. All of the desired results

B. Two of the desired results

C. One of the desired results

D. An error statement

A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));