( 难度:中等)在Hive中,以下哪个SQL语句是错误的A.hive> SELECT ID, NAME, o.AMOUNT, o.DATE > FROM CUSTOMERS c > LEFT OUTER JOIN ORDERS o > ON (ID = o.CUSTOMER_ID);B.hive> SELECT ID, NAME, o.AMOUNT, o.DATE > FROM CUSTOMERS c > RIGHT OUTER JOIN ORDERS o > ON (

题目
( 难度:中等)在Hive中,以下哪个SQL语句是错误的
A.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> LEFT OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
B.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> RIGHT OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
C.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> FULL OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
D.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> FULL OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID OR Name = o.Name);
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相似问题和答案

第1题:

ExhibitExamine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their manager‘s last names and their department names. Which query would you use?()

A. SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN department d ON (e.department_id = d.department_id);

B. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id) LEFT OUTER JOIN department d ON (e.department_id = d.department_id);

C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id) FULL OUTER JOIN department d ON (e.department_id = d.department_id);

D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGT OUTER JOIN department d ON (e.department_id = d.department_id);

E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)

F. SELECT last_name, manager_id, department_name FROM employees e JOIN department d ON (e.department_id = d.department_id);


参考答案:B

第2题:

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?()

A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);

B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;


参考答案:B

第3题:

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns:CUST_ID NUMBER(4) NOT NULLCUST_NAME VARCHAR2(100) NOT NULLCUST_ADDRESS VARCHAR2(150)CUST_PHONE VARCHAR2(20)Which SELECT statement accomplishes this task?()

A. SELECT* FROM customers;

B. SELECT name, address FROM customers;

C. SELECT id, name, address, phone FROM customers;

D. SELECT cust_name, cust_address FROM customers;

E. SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;


参考答案:D

第4题:

Given the following table definitions: EMPLOYEE ID NAME DEPTID 01Smith 10 02Bossy 20 03 20 Peterson 04Goss 30 05Pape 40 06Avery 50 07O'Neal 60 08Carter 50 DEPARTMENT ID DEPTNAME 05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id > 4 Which of the following queries will produce the same result set as the query above?()

  • A、SELECT e.id, d.deptname FROM employee e, department d WHERE e.id > 4
  • B、SELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id > 4
  • C、SELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id > 4
  • D、SELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4

正确答案:B

第5题:

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?()

  • A、SELECT* FROM customers;
  • B、SELECT name, address FROM customers;
  • C、SELECT id, name, address, phone FROM customers;
  • D、SELECT cust_name, cust_address FROM customers;
  • E、SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;

正确答案:D

第6题:

Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?()

A. SELECT last_name, department_name FROM employees , departments(+);

B. SELECT last_name, department_name FROM employees JOIN departments(+);

C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments d

D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E. SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);

F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);


参考答案:F

第7题:

Given the following table definitions:EMPLOYEEID NAME DEPTID01Smith 1002Bossy 2003 20Peterson04Goss 3005Pape 4006Avery 5007O‘Neal 6008Carter 50DEPARTMENT ID DEPTNAME05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id > 4Which of the following queries will produce the same result set as the query above?()

A.SELECT e.id, d.deptname FROM employee e, department d WHERE e.id > 4

B.SELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id > 4

C.SELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id > 4

D.SELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4


参考答案:B

第8题:

Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2 (30)JOB_ID VARCHAR2 (20)SALARY NUMBERMGR_ID NUMBER References EMPLOYEE_ID COLUMNDEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS tableDEPARTMENTSColumn name Data type RemarksDEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30)MGR_ID NUMBER References MGR_ID column of the EMPLOYEES tableEvaluate this SQL statement:SELECT employee_id, e.department_id, department_name, salaryFROM employees e, departments dWHERE e. department_id = d.department_id;Which SQL statement is equivalent to the above SQL statement? ()

A. SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);

B. SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;

C. SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;

D. SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);


参考答案:C

第9题:

Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?()

  • A、SELECT last_name, department_name FROM employees , departments(+);
  • B、SELECT last_name, department_name FROM employees JOIN departments(+);
  • C、SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments d
  • D、SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
  • E、SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);
  • F、SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);

正确答案:F

第10题:

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?()

  • A、SELECT last_name, department_name FROM employees NATURAL JOIN departments;
  • B、SELECT last_name, department_name FROM employees JOIN departments ;
  • C、SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);
  • D、SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
  • E、SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);
  • F、SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

正确答案:F

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